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Help me with my math homework!
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ijkm Offline
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Post: #1
Help me with my math homework!

Can somebody help me ? I'm grade 10. Tks. They want me to find "x".

1) [Image: 75a40.gif]
2) [Image: cc360.gif]
3) [Image: 8f187.gif]
(This post was last modified: 11-17-2011 03:28 PM by ijkm.)
11-17-2011 12:11 AM
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McGee! Offline
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Post: #2
RE: Help me with my math homework!

is thuis ment to be one problem?

Sociopath Wrote:
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Point is you can't censor reality.
U.S. Supreme Court Justice Abe Fortas, Tinker v. Des Moines (1969) Wrote:In our system, state-operated schools may not be enclaves of totalitarianism. School officials do not possess absolute authority over their students. Students in school as well as out of school are "persons" under our Constitution."
Rebelnerd Wrote:Human rights are being violated by US law enforcement. This is what the media is here for, you're supposed to be the watchdogs! You're supposed to stand up for the downtrodden, not belittle them as though all their problems amount to nothing more than some angry glares toward parents and sabotaging their computers.
I've seen so much shit done to youth and for some reason, this has made me angrier than I've felt in years. Abuse and oppression happens all over the world. It's a terrible reality of modern society, but we've all accepted that it happens and we're doing what we can to fight it and build a better world.
But this...this mindless, condescending disrespect toward people who have no legal voice with which to defend themselves, this reduction of parents' betrayal into a cheap crack about kids being computer-savvy...it's like watching a surgeon joke about life insurance while his patient bleeds to death on the operating table. The media's job is to protect society from oppression and they've drawn a clear line between the people worth protecting and the people that don't matter. How can they people sleep at night?

You're a journalist. DO. YOUR. FUCKING. JOB.

(04-28-2010 08:17 AM)Liquid Wrote:  Laws never seem to help people fight School. Laws only matter if the students are braking them...

(12-03-2011 07:40 AM)SoulRiser Wrote:  Solution to all these problems: don't fuck people you can't negotiate with in a civilized manner.
(02-09-2012 02:14 PM)Absentinsomniac Wrote:  The only solution is democratic self-paced education where students can excel in what they are good at and work on what their not if necessary, AT THEIR OWN DAMN PACE IN THEIR OWN DAMN WAY.



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11-17-2011 07:00 AM
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LOON_ATTIC Offline
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Post: #3
RE: Help me with my math homework!

What do they want you to do with that, factoring and expanding?

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11-17-2011 12:47 PM
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Aya Offline
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RE: Help me with my math homework!

Wow those are some ugly little bastards aren't they? I'll work on them later tonight and post answers tomorrow. iPhone isn't great with writing out equations.
11-17-2011 01:10 PM
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LOON_ATTIC Offline
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RE: Help me with my math homework!

Huh I suppose they want you to solve them algebraically :|

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11-17-2011 01:12 PM
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Aya Offline
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RE: Help me with my math homework!

It's a mix of pemdas and factoring.
11-17-2011 01:14 PM
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ijkm Offline
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RE: Help me with my math homework!

Hmm , they want me to find "x".
11-17-2011 03:10 PM
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Absnt Offline
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RE: Help me with my math homework!

Lol, I'd start at the bottom, distribute, and see what you can derive from there. The top seems useless until you have a little more info.

Fuck this, I'm not even going to do my own math homework let alone yours lol.

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11-17-2011 03:17 PM
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DUBAS Offline
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RE: Help me with my math homework!

That's pretty easy.

First, move everything from one side to the equal sign to the other.
It should look something like:

allnumbersandxsonthisside=0

Next, if you have something we call here as a ''common factor'' extract it.
It's done something like, if you have this:

(20x+50x) you can extract the x and make it like this: x(20+50). As you can see it's made much easier for logical reasons. Do that whenever you can. Once done and you have everything on one side, common factors out and such you should have x's and x's squared. The formula you have to apply I forget but just look it up. One thing I DO remember is that once you have everything on that side you should arrange it in the following way, if the case is this:

2xsquared+5x you should name the first one a and the second one b. Substitute as it says in the formula you look up, do the math and you should get two answers, one positive and one negative.

I aced that test, it's really simple.

Now you should be able to do the math. It's hard explaining over a forum so you should look it up on youtube or something.

Anyways, you're welcome!

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11-18-2011 04:18 AM
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Aya Offline
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RE: Help me with my math homework!

(11-17-2011 03:10 PM)ijkm Wrote:  Hmm , they want me to find "x".

Lol, Well at least you know where to start.
11-18-2011 07:44 AM
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Rosemary16 Offline
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Post: #11
RE: Help me with my math homework!

(11-17-2011 12:11 AM)ijkm Wrote:  Can somebody help me ? I'm grade 10. Tks. They want me to find "x".

1) [Image: 75a40.gif]
2) [Image: cc360.gif]
3) [Image: 8f187.gif]

Maybe an example could help. This may help you with problem 1.

18 * x^2 - 18 * x * sqrt(x) - 17 * x - 8 * sqrt(x) - 2 = 0

if x = 4

18 * 4^2 - 18 * 4 * sqrt(4) - 17 * 4 - 8 * sqrt(4) - 2

18 * 4^2 - 18 * 4 * 2 - 17 * 4 - 8 * 2 - 2

18 * 16 - 18 * 4 * 2 - 17 * 4 - 8 * 2 - 2

288 - 144 - 68 - 16 - 2

288 - 144 = 144, 144 - 68 = 76, 76 - 16 = 60, 60 - 2 = 58
12-17-2011 08:19 AM
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LOON_ATTIC Offline
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Post: #12
RE: Help me with my math homework!

wat, I'm in precalculus and I have no idea how to solve the first one, except with a graphing calculator or something

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12-17-2011 09:55 AM
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Sunbourn Offline
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Post: #13
RE: Help me with my math homework!

(12-17-2011 09:55 AM)Lunatic Wrote:  wat, I'm in precalculus and I have no idea how to solve the first one, except with a graphing calculator or something

I'm in Trig and I have no idea what to do with that crap either. OP's teacher hates them.

I tried solving the second one, by multiplying each term in the first parenthesis with each term in the second parenthesis. Basically FOIL but with three terms. I ended up with a Quartic root, and I'm not familiar with the Quartic or Cubic formula so I stopped there. I'm guessing there's an easier way to solve it and I just overcomplicated it.

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12-17-2011 09:59 AM
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Aya Offline
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RE: Help me with my math homework!

I tried to do the bottom one and I filled the whole page before I gave up.
(This post was last modified: 12-17-2011 10:01 AM by Aya.)
12-17-2011 10:00 AM
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Rosemary16 Offline
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RE: Help me with my math homework!

(12-17-2011 09:59 AM)|55555| Wrote:  
(12-17-2011 09:55 AM)Lunatic Wrote:  wat, I'm in precalculus and I have no idea how to solve the first one, except with a graphing calculator or something

I'm in Trig and I have no idea what to do with that crap either. OP's teacher hates them.

I tried solving the second one, by multiplying each term in the first parenthesis with each term in the second parenthesis. Basically FOIL but with three terms. I ended up with a Quartic root, and I'm not familiar with the Quartic or Cubic formula so I stopped there. I'm guessing there's an easier way to solve it and I just overcomplicated it.

You are seriously overcomplicating it, because I understand graphing as a coordinate grid, I only used square roots, 1 square, lots of multiplacation, and some subtraction. I also did it in that order. I use PREMDAS with R standing for roots.

However, If you must know about cube roots or quadric roots or even quintatic roots, look at the power of the root. I always do roots backwards, since I don't understand how to solve the square root of 5 or anything like that without a calculator.

Examples:

Cuberoot(729)
9^3 = 729
Cuberoot(729) = 9

Quadroot(256)
4^4 = 256
Quadroot(256) = 4

Quinroot(759,375)
15^5 = 759,375
Quinroot(759,375) = 15

Yes, I did use a calculator.
(This post was last modified: 12-17-2011 10:22 AM by Rosemary16.)
12-17-2011 10:22 AM
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Sunbourn Offline
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RE: Help me with my math homework!

(12-17-2011 10:22 AM)Rosemary16 Wrote:  
(12-17-2011 09:59 AM)|55555| Wrote:  
(12-17-2011 09:55 AM)Lunatic Wrote:  wat, I'm in precalculus and I have no idea how to solve the first one, except with a graphing calculator or something

I'm in Trig and I have no idea what to do with that crap either. OP's teacher hates them.

I tried solving the second one, by multiplying each term in the first parenthesis with each term in the second parenthesis. Basically FOIL but with three terms. I ended up with a Quartic root, and I'm not familiar with the Quartic or Cubic formula so I stopped there. I'm guessing there's an easier way to solve it and I just overcomplicated it.

You are seriously overcomplicating it, because I understand graphing as a coordinate grid, I only used square roots, 1 square, lots of multiplacation, and some subtraction. I also did it in that order. I use PREMDAS with R standing for roots.

However, If you must know about cube roots or quadric roots or even quintatic roots, look at the power of the root. I always do roots backwards, since I don't understand how to solve the square root of 5 or anything like that without a calculator.

Examples:

Cuberoot(729)
9^3 = 729
Cuberoot(729) = 9

Quadroot(256)
4^4 = 256
Quadroot(256) = 4

Quinroot(759,375)
15^5 = 759,375
Quinroot(759,375) = 15

Yes, I did use a calculator.
I don't see how you can use that info to solve the second one, nor does my friend majoring in mathematics. We're probably just missing something.

If you showed us how to do it on the 2nd problem we'd probably understand. I'm really interested in seeing how it works out.

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12-17-2011 10:54 AM
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jonsenjohn Offline
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Smile  Math Worksheets

There is very good link for help to home work ... We feature over 2,000 free math printables that range in skill from grades K-12. Please use all of our printables to make your day easier. Great for students, teachers, parents, and tutors. This is really helps for us...Thank for this...Mwahaha
Math Worksheets
(This post was last modified: 04-12-2012 04:53 AM by jonsenjohn.)
04-12-2012 04:52 AM
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Stadium Offline
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RE: Help me with my math homework!

[Image: x.jpg]

And obviously don't click on the link from the guy with 1 post above me.

No, this is Patrick.
04-12-2012 08:25 AM
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