Help me with my math homework!

[ijkm]

Can somebody help me ? I'm grade 10. Tks. They want me to find "x".

1)
2)
3)

[McGee!]

is thuis ment to be one problem?

[Lunatic]

What do they want you to do with that, factoring and expanding?

[Aya]

Wow those are some ugly little bastards aren't they? I'll work on them later tonight and post answers tomorrow. iPhone isn't great with writing out equations.

[Lunatic]

Huh I suppose they want you to solve them algebraically :|

[Aya]

It's a mix of pemdas and factoring.

[ijkm]

Hmm , they want me to find "x".

[Absentinsomniac]

Lol, I'd start at the bottom, distribute, and see what you can derive from there. The top seems useless until you have a little more info.

Fuck this, I'm not even going to do my own math homework let alone yours lol.

[DUBAS]

That's pretty easy.

First, move everything from one side to the equal sign to the other.
It should look something like:

allnumbersandxsonthisside=0

Next, if you have something we call here as a ''common factor'' extract it.
It's done something like, if you have this:

(20x+50x) you can extract the x and make it like this: x(20+50). As you can see it's made much easier for logical reasons. Do that whenever you can. Once done and you have everything on one side, common factors out and such you should have x's and x's squared. The formula you have to apply I forget but just look it up. One thing I DO remember is that once you have everything on that side you should arrange it in the following way, if the case is this:

2xsquared+5x you should name the first one a and the second one b. Substitute as it says in the formula you look up, do the math and you should get two answers, one positive and one negative.

I aced that test, it's really simple.

Now you should be able to do the math. It's hard explaining over a forum so you should look it up on youtube or something.

Anyways, you're welcome!

[Aya]

(11-17-2011 03:10 PM)ijkm Wrote:  Hmm , they want me to find "x".

Lol, Well at least you know where to start.

[Rosemary16]

(11-17-2011 12:11 AM)ijkm Wrote:  Can somebody help me ? I'm grade 10. Tks. They want me to find "x".

1)
2)
3)

Maybe an example could help. This may help you with problem 1.

18 * x^2 - 18 * x * sqrt(x) - 17 * x - 8 * sqrt(x) - 2 = 0

if x = 4

18 * 4^2 - 18 * 4 * sqrt(4) - 17 * 4 - 8 * sqrt(4) - 2

18 * 4^2 - 18 * 4 * 2 - 17 * 4 - 8 * 2 - 2

18 * 16 - 18 * 4 * 2 - 17 * 4 - 8 * 2 - 2

288 - 144 - 68 - 16 - 2

288 - 144 = 144, 144 - 68 = 76, 76 - 16 = 60, 60 - 2 = 58

[Lunatic]

wat, I'm in precalculus and I have no idea how to solve the first one, except with a graphing calculator or something

[|55555|]

(12-17-2011 09:55 AM)Lunatic Wrote:  wat, I'm in precalculus and I have no idea how to solve the first one, except with a graphing calculator or something

I'm in Trig and I have no idea what to do with that crap either. OP's teacher hates them.

I tried solving the second one, by multiplying each term in the first parenthesis with each term in the second parenthesis. Basically FOIL but with three terms. I ended up with a Quartic root, and I'm not familiar with the Quartic or Cubic formula so I stopped there. I'm guessing there's an easier way to solve it and I just overcomplicated it.

[Aya]

I tried to do the bottom one and I filled the whole page before I gave up.

[Rosemary16]

(12-17-2011 09:59 AM)|55555| Wrote:  

(12-17-2011 09:55 AM)Lunatic Wrote:  wat, I'm in precalculus and I have no idea how to solve the first one, except with a graphing calculator or something

I'm in Trig and I have no idea what to do with that crap either. OP's teacher hates them.

I tried solving the second one, by multiplying each term in the first parenthesis with each term in the second parenthesis. Basically FOIL but with three terms. I ended up with a Quartic root, and I'm not familiar with the Quartic or Cubic formula so I stopped there. I'm guessing there's an easier way to solve it and I just overcomplicated it.

You are seriously overcomplicating it, because I understand graphing as a coordinate grid, I only used square roots, 1 square, lots of multiplacation, and some subtraction. I also did it in that order. I use PREMDAS with R standing for roots.

However, If you must know about cube roots or quadric roots or even quintatic roots, look at the power of the root. I always do roots backwards, since I don't understand how to solve the square root of 5 or anything like that without a calculator.

Examples:

Cuberoot(729)
9^3 = 729
Cuberoot(729) = 9

Quadroot(256)
4^4 = 256
Quadroot(256) = 4

Quinroot(759,375)
15^5 = 759,375
Quinroot(759,375) = 15

Yes, I did use a calculator.

[|55555|]

(12-17-2011 10:22 AM)Rosemary16 Wrote:  

(12-17-2011 09:59 AM)|55555| Wrote:  

(12-17-2011 09:55 AM)Lunatic Wrote:  wat, I'm in precalculus and I have no idea how to solve the first one, except with a graphing calculator or something

I'm in Trig and I have no idea what to do with that crap either. OP's teacher hates them.

I tried solving the second one, by multiplying each term in the first parenthesis with each term in the second parenthesis. Basically FOIL but with three terms. I ended up with a Quartic root, and I'm not familiar with the Quartic or Cubic formula so I stopped there. I'm guessing there's an easier way to solve it and I just overcomplicated it.

You are seriously overcomplicating it, because I understand graphing as a coordinate grid, I only used square roots, 1 square, lots of multiplacation, and some subtraction. I also did it in that order. I use PREMDAS with R standing for roots.

However, If you must know about cube roots or quadric roots or even quintatic roots, look at the power of the root. I always do roots backwards, since I don't understand how to solve the square root of 5 or anything like that without a calculator.

Examples:

Cuberoot(729)
9^3 = 729
Cuberoot(729) = 9

Quadroot(256)
4^4 = 256
Quadroot(256) = 4

Quinroot(759,375)
15^5 = 759,375
Quinroot(759,375) = 15

Yes, I did use a calculator.

I don't see how you can use that info to solve the second one, nor does my friend majoring in mathematics. We're probably just missing something.

If you showed us how to do it on the 2nd problem we'd probably understand. I'm really interested in seeing how it works out.

[jonsenjohn]

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[Stadium]

And obviously don't click on the link from the guy with 1 post above me.