 Heya: Your local math-dimwit here come for some help - Printable Version +- School Survival Forums (http://forums.school-survival.net) +-- Forum: Learning, Youth Rights and School Survival (/forumdisplay.php?fid=3) +--- Forum: Homework Help & Answers (/forumdisplay.php?fid=30) +--- Thread: Heya: Your local math-dimwit here come for some help (/showthread.php?tid=6030) Heya: Your local math-dimwit here come for some help - IllusoryDeath - 01-13-2010 11:49 AM Howdy. Help with these two, please? ....I'm 17, currently a junior in an IB college prep high school, and both of these 'simple' word problems are giving me a headache. This is like, what, pre-algebraic stuff? Pathetic. I do have to place the blame, however, upon the schools/mathematics classes that I have been in: From the confession's topic: IllusoryDeath Wrote:I confess that my state is known for being the second-worst in the entire nation when it comes to statewide math scores; Detroit being numero uno when it comes to suck-assishness in the math dept. Here are the little buggers:  Re: Heya: Your local math-dimwit here come for some help - magikarp - 01-13-2010 01:01 PM Basically, you just write down a bunch of equations. There are 50 coins. x + y + z = 50 They add up to 120 cents x + 2y + 5z = 120 There are twice as many 2-cent coins as 1-cent coins. 2x = y Then you can solve. Since y= 2x, you can replace it in the other equations. x + 2(2x) + 5z = 120 5x + 5z = 120 x + z = 24 x + 2x + z = 50 3x + z = 50 Now it's probably easiest to solve for z in terms of x. z = 24 - x z = 50 - 3x Now, since they both equal z, they also equal each other. 50 - 3x = 24 - x 26 = 2x x = 13 So there are 13 1-cent coins. It's pretty easy to find the 2-cent coins now, because there are twice as many. 2(13) = y 26 = y Now use one of the original equations to solve for z. (Can really be anything at this point as long as it includes z.) 13 + 26 + z = 50 z = 50 - 39 z = 11 The next one's simpler. There are 50 stamps. x + y = 50 Their total value is 202 cents. 2x + 5y = 202 Just solve each for y in terms of x. y = 50 - x 5y = 202 - 2x y = (202 - 2x) /5 Now put them together again. (202 - 2x)/ 5 = 50 - x 202 - 2x = 250 - 5x 3x = 48 x = 16 Done, but you can still solve for y if you want to check. 16 + y = 50 y = 34 16(2) + 34(5) = 32 + 170 = 202 , so it works. Re: Heya: Your local math-dimwit here come for some help - Loxor - 01-13-2010 03:52 PM OH, that is what I was doing wrong in problem two. Damn distributive property, or whatever. Re: Heya: Your local math-dimwit here come for some help - IllusoryDeath - 01-14-2010 11:23 AM AAAAAAAAAAAAAAH, thank you magikarp. Wish my math studies teacher could explain the process in as simple terms as you have. Re: Heya: Your local math-dimwit here come for some help - aerftghyjk - 01-16-2010 11:21 AM 1. Lisa is a fictional character on the Simpsons, and therefor does not have ANY money. So the answers are 0. 2. Steve was recently robbed at gun point, so he has no money. Even worse: He died. But yeah, those are the answers. Re: Heya: Your local math-dimwit here come for some help - IllusoryDeath - 01-17-2010 02:35 AM But but but...Steve NEEDS stamps!!!!!!!!!! D8